Exercise


May 04'23

Answer

Solution: E

[[math]] \begin{align*} M(t_1,t_2) = E[e^{t_1W + t_2Z}] = E[e^{t_1(X+Y) + t_2(Y-X)}] &= E[e^{(t_1-t_2)X}e^{(t_1 + t_2)Y}] \\ &=E[e^{(t_1-t_2)X}]E[e^{(t_1 + t_2)Y}] \\ &= e^{\frac{1}{2}(t_1-t_2)^2}e^{\frac{1}{2}(t_1+t_2)^2} \\ &= e^{\frac{1}{2}(t_1^2 - 2t_1t_2 +t_2^2)} e^{\frac{1}{2}(t_1^2 + 2t_1t_2 + t_2^2)} \\ &= e^{t_1^2 + t_2^2} \end{align*} [[/math]]

Copyright 2023. The Society of Actuaries, Schaumburg, Illinois. Reproduced with permission.

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