Exercise
Nov 26'23
Answer
Solution: C
Child 1 needs [math]X v^3+Y v^{21-1}[/math].
Child 2 needs [math]X v^3+Y v^{21-3}[/math].
Child 3 needs [math]X v^3+Y v^{21-6}[/math]
So total amount needed is [math]3 X v^3+Y\left(v^{20}+v^{18}+v^{15}\right)[/math].
References
Hlynka, Myron. "University of Windsor Old Tests 62-392 Theory of Interest". web2.uwindsor.ca. Retrieved November 23, 2023.