Revision as of 22:04, 6 May 2023 by Admin (Created page with "'''Solution: B''' Let X and Y be the miles driven by the two cars. The total cost, is then <math display = "block"> C = 3(X/15 + Y/30) = 0.2X + 0.1Y. </math> C has a normal...")
Exercise
May 06'23
Answer
Solution: B
Let X and Y be the miles driven by the two cars. The total cost, is then
[[math]]
C = 3(X/15 + Y/30) = 0.2X + 0.1Y.
[[/math]]
C has a normal distribution with mean 0.2(25) + 0.1(25) = 7.5 and variance 0.04(9) + 0.01(9) = 0.45. Then,
[[math]]
\operatorname{P}(C \lt 7) = \operatorname{P}(Z \lt (7-7.5)/\sqrt{0.45} = -0.7454) = 0.23.
[[/math]]
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