May 25'23

Exercise

You are given:

  • The random walk model
    [[math]]y_t = y_0 + c_1 + c_2 + \cdots c_t[[/math]]
  • where [math]c_t, t = 0,1,2,\cdots, T [/math] denote observations from a white noise process.
  • The following nine observed values of [math]c_t[/math]:
    t yt
    1 2
    2 5
    3 10
    4 13
    5 18
    6 20
    7 24
    8 25
    9 27
    10 30
  • [math]y_0 = 0 [/math]
  • The 9 step ahead forecast of [math]y_{19}[/math] , [math]\hat{y}_{19}[/math] , is estimated based on the observed value of [math]y_{10}[/math] .

Calculate the standard error of the 9 step-ahead forecast, [math]\hat{y}_{19}[/math] .

  • 4/3
  • 4
  • 9
  • 12
  • 16

Copyright 2023. The Society of Actuaries, Schaumburg, Illinois. Reproduced with permission.

1 Answer
May 26'23

Key: B

[math]c= y_t − y_{t−1}[/math] and hence [math]c_1, c_2 ,\ldots c_{10} = 2,3,5,3,5, 2, 4,1, 2,3.[/math]

The mean of the [math]c[/math] values is 3, the variance is (1+0+4+0+4+1+1+4+1+0)/9 = 16/9. The standard deviation is 4/3. The standard error of the forecast is [math](4/3)\sqrt{9} = 4. [/math]

Copyright 2023. The Society of Actuaries, Schaumburg, Illinois. Reproduced with permission.

00
Comments
You are not permitted to add comments. Make sure you are logged in and your email has been confirmed.