Jan 17'24

Exercise

In a mortality study, the following grouped death data were collected from 100 lives, all studied beginning at age 40 .

Age last birthday at death Number of deaths
[math]40-49[/math] 10
[math]50-59[/math] 14
[math]60-69[/math] 16
[math]70-79[/math] 20
80 and higher 40

There were no terminations other than death.

Calculate [math]\hat{S}_{40}(32)[/math] using the ogive empirical distribution function.

  • 0.44
  • 0.48
  • 0.52
  • 0.56
  • 0.60

Copyright 2024. The Society of Actuaries, Schaumburg, Illinois. Reproduced with permission.

1 Answer
Jan 17'24

Answer: D

[math]\hat{S}(30)=\frac{100-10-14-16}{100}=0.60, \quad \hat{S}(40)=\frac{100-10-14-16-20}{100}=0.40[/math]

Use linear interpolation to find [math]\hat{S}(32)[/math]

[math]\hat{S}(32)=\left(\frac{40-32}{40-30}\right) \hat{S}(30)+\left(\frac{32-30}{40-30}\right) \hat{S}(40)+=0.8(0.60)+0.2(0.40)=0.56[/math]

Copyright 2024. The Society of Actuaries, Schaumburg, Illinois. Reproduced with permission.

00
Comments
You are not permitted to add comments. Make sure you are logged in and your email has been confirmed.