Revision as of 16:22, 14 May 2023 by Admin (Created page with "'''Key: B''' Mean excess loss = <math display = "block"> \frac{\operatorname{E}(X) - \operatorname{E}(X \wedge 100)}{1-F(100)} = \frac{331-91}{0.8} = 300 </math> Note that...")
Exercise
May 14'23
Answer
Key: B
Mean excess loss =
[[math]]
\frac{\operatorname{E}(X) - \operatorname{E}(X \wedge 100)}{1-F(100)} = \frac{331-91}{0.8} = 300
[[/math]]
Note that [math]\operatorname{E}( X ) = \operatorname{E}( X \wedge 1000)[/math] because [math]F(1000) = 1.[/math]