Revision as of 14:40, 13 May 2023 by Admin (Created page with "'''Key: D''' <math display = "block"> \begin{aligned} L( p ) &= f (0.74) f (0.81) f (0.95) = ( p + 1)0.74 p ( p + 1)0.81 p ( p + 1)0.95 p \\ & = ( p + 1)3 (0.56943) p \\ l( p...")
Exercise
May 13'23
Answer
Key: D
[[math]]
\begin{aligned}
L( p ) &= f (0.74) f (0.81) f (0.95) = ( p + 1)0.74 p ( p + 1)0.81 p ( p + 1)0.95 p \\
& = ( p + 1)3 (0.56943) p \\
l( p ) &= \ln L( p) = 3\ln( p + 1) + p \ln(0.56943) \\
&= l^{'}(p) = \frac{3}{p+1} - 0.563119 = 0 \\
&= p + 1 = \frac{3}{0.563119} = 5.32747, p = 4.32747.
\end{aligned}
[[/math]]
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