exercise:Cb32047610: Difference between revisions

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<math display = "block">
<math display = "block">
f(t) = \begin{cases}
F(l) = \begin{cases}
\frac{3}{4}\left(\frac{l}{V}\right)^3, \, 0 ≤ l < V \\
\frac{3}{4}\left(\frac{l}{V}\right)^3, \, 0 ≤ l < V \\
1-\frac{1}{10}e^{\frac{-(l-V)}{V}}, \, \textrm{otherwise}
1-\frac{1}{10}e^{\frac{-(l-V)}{V}}, \, \textrm{otherwise}

Latest revision as of 21:20, 8 May 2023

Individuals purchase both collision and liability insurance on their automobiles. The value of the insured’s automobile is V. Assume the loss L on an automobile claim is a random variable with cumulative distribution function

[[math]] F(l) = \begin{cases} \frac{3}{4}\left(\frac{l}{V}\right)^3, \, 0 ≤ l \lt V \\ 1-\frac{1}{10}e^{\frac{-(l-V)}{V}}, \, \textrm{otherwise} \end{cases} [[/math]]

Calculate the probability that the loss on a randomly selected claim is greater than the value of the automobile.

  • 0.00
  • 0.10
  • 0.25
  • 0.75
  • 0.90

Copyright 2023. The Society of Actuaries, Schaumburg, Illinois. Reproduced with permission.