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| rev | Admin | (Created page with "'''Answer: A''' The median of <math>K_{48}</math> is the integer <math>m</math> for which <math display="block"> P\left(K_{48} < m\right) \leq 0.5 \text { and } P\left(K_{48} > m\right) \leq 0.5 \text {. } </math> This is equivalent to finding <math>m</math> for which <math display="block"> \frac{l_{48+m}}{l_{48}} \geq 0.5 \text { and } \frac{l_{48+m+1}}{l_{48}} \leq 0.5 </math> Based on the SULT and <math>l_{48}(0.5)=(98,783.9)(0.5)=49,391.95</math>, we have...") | Jan 18'24 at 12:29 | +790 |