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| rev | Admin | (Created page with "'''Answer: A''' <math display="block"> \begin{aligned} \operatorname{Var}(Z) & =E\left(Z^{2}\right)-E(Z)^{2} \\ E(Z) & =E\left[(1+0.2 T)(1+0.2 T)^{-2}\right]=E\left[(1+0.2 T)^{-1}\right] \\ & =\int_{0}^{40} \frac{1}{(1+0.2 t)} f_{T}(t) d t=\frac{1}{40} \int_{0}^{40} \frac{1}{1+0.2 t} d t \\ & =\left.\frac{1}{40} \frac{1}{0.2} \ln (1+0.2 t)\right|_{0} ^{40}=\frac{1}{8} \ln (9)=0.27465 \\ E\left(Z^{2}\right) & =E\left\{(1+0.2 T)^{2}\left[(1+0.2 T)^{-2}\right]^{2}\right\}...") | Jan 18'24 at 11:36 | +803 |