Revision as of 18:01, 17 January 2024 by Admin (Created page with "An insurer is modelling time to death of lives insured at age <math>x</math> using the Kaplan-Meier estimator. You are given the following information. (i) There were 100 policies in force at time 0 (ii) There were no new policies entering the study (iii) At time 10.0, immediately after a death, there were 50 policies remaining in force (iv) The Kaplan-Meier estimate of the survival function for death at time 10 is <math>\hat{S}(10.0)=0.92</math> (v) The next death...")
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Jan 17'24

Exercise

An insurer is modelling time to death of lives insured at age [math]x[/math] using the Kaplan-Meier estimator. You are given the following information.

(i) There were 100 policies in force at time 0

(ii) There were no new policies entering the study

(iii) At time 10.0, immediately after a death, there were 50 policies remaining in force

(iv) The Kaplan-Meier estimate of the survival function for death at time 10 is [math]\hat{S}(10.0)=0.92[/math]

(v) The next death after time 10.0 occurred when there was one death at time 10.8

(vi) During the period from time 10.0 to time 10.8 , a total of 10 policies terminated for reasons other than death

Calculate [math]\hat{S}(10.8)[/math], the Kaplan-Meier estimate of the survival function [math]S(10.8)[/math].

  • 0.897
  • 0.903
  • 0.909
  • 0.910
  • 0.920
1 Answer
Jan 17'24

Answer: A

[math]\hat{S}(10.8)=\hat{S}(10.0)\left(\frac{50-10-1}{50-10}\right)=0.897[/math]

Copyright 2024. The Society of Actuaries, Schaumburg, Illinois. Reproduced with permission.

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