You are given:
(i) [math]\quad S_{0}(t)=\left(1-\frac{t}{\omega}\right)^{\frac{1}{4}}[/math], for [math]0 \leq t \leq \omega[/math]
(ii) [math]\quad \mu_{65}=\frac{1}{180}[/math]
Calculate [math]e_{106}[/math], the curtate expectation of life at age 106 .
- 2.2
- 2.5
- 2.7
- 3.0
- 3.2
Scientists are searching for a vaccine for a disease. You are given:
(i) 100,000 lives age [math]x[/math] are exposed to the disease
(ii) Future lifetimes are independent, except that the vaccine, if available, will be given to all at the end of year 1
(iii) The probability that the vaccine will be available is 0.2
(iv) For each life during year [math]1, q_{x}=0.02[/math]
(v) For each life during year 2, [math]q_{x+1}=0.01[/math] if the vaccine has been given, and [math]q_{x+1}=0.02[/math] if it has not been given
Calculate the standard deviation of the number of survivors at the end of year 2.
- 100
- 200
- 300
- 400
- 500
You are given the following survival function of a newborn:
Calculate the probability that (30) dies within the next 20 years.
- 0.13
- 0.15
- 0.17
- 0.19
- 0.21
In a population initially consisting of [math]75 \%[/math] females and [math]25 \%[/math] males, you are given:
(i) For a female, the force of mortality is constant and equals [math]\mu[/math]
(ii) For a male, the force of mortality is constant and equals [math]1.5 \mu[/math]
(iii) At the end of 20 years, the population is expected to consist of [math]85 \%[/math] females and [math]15 \%[/math] males
Calculate the probability that a female survives one year.
- 0.89
- 0.92
- 0.94
- 0.96
- 0.99
You are given that mortality follows Makeham's Law with the following parameters:
Let [math]L_{15}[/math] be the random variable representing the number of lives alive at the end of 15 years if there are 10,000 lives age 50 at time 0 .
Calculate [math]\operatorname{Var}\left[L_{15}\right][/math].
- 1,317
- 1,328
- 1,339
- 1,350
- 1,361
You are given:
i)[math] q_{80}=0.04[/math]
ii)[math] q_{81}=0.06[/math]
iii)[math]q_{82}=0.08[/math]
iv) Deaths between ages 80 and 81 are uniformly distributed
v) Deaths between ages 81 and 82 are subject to a constant force of mortality
Calculate the probability that a person aged 80.6 will die between ages 81.1 and 81.6.
- 0.0294
- 0.0296
- 0.0298
- 0.0300
- 0.0302
For a new light bulb, you are given:
i) [math]{ }_{t} q_{0}=\frac{t^{2}+t}{72}[/math] for [math]0 \leq t \leq 8[/math]
ii) [math]T_{0}[/math] is the random variable representing the future lifetime
Calculate [math]\operatorname{Var}\left[T_{0}\right][/math].
- 3.9
- 4.1
- 4.3
- 4.5
- 4.7
You are given the following:
(i) [math] e_{40:20}=18[/math]
(ii) [math]e_{60}=25[/math]
(iii) [math]{ }_{20} q_{40}=0.2[/math]
(iv) [math]q_{40}=0.003[/math]
Calculate [math]e_{41}[/math].
- 36.1
- 37.1
- 38.1
- 39.1
- 40.1